3v^2+8v=0

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Solution for 3v^2+8v=0 equation: 



3v^2+8v=0

a = 3; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·3·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$


$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*3}=\frac{-16}{6}
=-2+2/3
$


$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*3}=\frac{0}{6}
=0
$

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